628. Maximum Product of Three Numbers
Given an integer array, find three numbers whose product is maximum and output the maximum product.
Example 1:
Input: [1,2,3]
Output: 6
Example 2:
Input: [1,2,3,4]
Output: 24
Note:
The length of the given array will be in range [3,104] and all elements are in the range [-1000, 1000].
Multiplication of any three numbers in the input won't exceed the range of 32-bit signed integer.
class Solution {
public int maximumProduct(int[] nums) {
if(nums == null || nums.length == 0) return 0;
int min1 = Integer.MAX_VALUE, min2 = Integer.MAX_VALUE;
int max1 = Integer.MIN_VALUE,max2 = Integer.MIN_VALUE, max3 = Integer.MIN_VALUE;
for(int n : nums){
if(n < min1){
min2 = min1;
min1 = n;
}
else if(n < min2){
min2 = n;
}
if(n > max1){
max3 = max2;
max2 = max1;
max1 = n;
}else if(n > max2){
max3 = max2;
max2 = n;
}else if(n > max3){
max3 = n;
}
}
return Math.max(min1*min2*max1, max1*max2*max3);
}
}
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