Two Sum II - Input array is sorted
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.
Note:
Your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution and you may not use the same element twice.
Example:
Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.
class Solution {
public int[] twoSum(int[] numbers, int target) {
if(numbers == null || numbers.length == 0){
return new int[0];
}
int start = 0, end = numbers.length-1;
int[] res = new int[2];
while(start < end){
if(numbers[start] + numbers[end] == target){
res[0] = start+1;
res[1] = end+1;
return res;
}
else if(numbers[start] + numbers[end] < target){
start++;
}else{
end--;
}
}
return res;
}
}
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