Word Break

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

Note:

• The same word in the dictionary may be reused multiple times in the segmentation.

• You may assume the dictionary does not contain duplicate words.

Example 1:

Input: s = "leetcode", wordDict = ["leet", "code"]
Output: true
Explanation: Return true because "leetcode" can be segmented as "leet code".

Example 2:

Input: s = "applepenapple", wordDict = ["apple", "pen"]
Output: true
Explanation: Return true because "applepenapple" can be segmented as "apple pen apple".
             Note that you are allowed to reuse a dictionary word.

Example 3:

Input: s = "catsandog", wordDict = ["cats", "dog", "sand", "and", "cat"]
Output: false

time o(n^2), space o(n)

Loading...LeetCode

子问题：左边字符串是不是可以组成词+右边的字符串是不是在词典里

class Solution {
    public boolean wordBreak(String s, List<String> wordDict) {
        
        
        
        boolean[] dp = new boolean[s.length()+1];
        dp[0] = true;
        for(int i = 1; i <= s.length();i++){
            for(int j = 0; j< i;j++){
                if(dp[j] && wordDict.contains(s.substring(j,i))){
                    dp[i] = true;
                    break;
                }
            }
        }
        
        return dp[s.length()];
    }
}