All Paths From Source to Target

Given a directed, acyclic graph of N nodes. Find all possible paths from node 0 to node N-1, and return them in any order.

The graph is given as follows: the nodes are 0, 1, ..., graph.length - 1. graph[i] is a list of all nodes j for which the edge (i, j) exists.

Example:
Input: [[1,2], [3], [3], []] 
Output: [[0,1,3],[0,2,3]] 
Explanation: The graph looks like this:
0--->1
|    |
v    v
2--->3
There are two paths: 0 -> 1 -> 3 and 0 -> 2 -> 3.

Note:

  • The number of nodes in the graph will be in the range [2, 15].

  • You can print different paths in any order, but you should keep the order of nodes inside one path.

class Solution {
    public List<List<Integer>> allPathsSourceTarget(int[][] graph) {
        List<List<Integer>> res = new ArrayList<>();
        if(graph == null || graph.length == 0 || graph[0].length == 0) return res;
        List<Integer> list = new ArrayList<>();
        list.add(0);
        dfs(graph,0,res,list) ;
        
        return res;
    }
    
    public void dfs(int[][] graph, int cur, List<List<Integer>> res, List<Integer> list){
        if(cur == graph.length - 1) res.add(new ArrayList<>(list));
        
        else 
            for(int nei : graph[cur]){
                list.add(nei);
                dfs(graph,nei,res,list);
                list.remove(list.size() -1 );
            }
    }
    
   
}

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